Given two numbers $x, y$. You need to determine if there exists an integer $n$ such that $S(n) = x$, $S(n + 1) = y$.

Here, $S(a)$ denotes the sum of the digits of the number $a$ in the decimal numeral system.

Input

Each test contains multiple test cases. The first line contains the number of test cases $t$ ($1 \le t \le 500$). The description of the test cases follows.

The first line of each test case contains two integers $x, y$ ($1 \le x \le 1000, 1 \le y \le 1000$).

Output

For each test case, print "NO" if a suitable $n$ does not exist. Otherwise, output "YES".

You can output each letter in any case (for example, "YES", "Yes", "yes", "yEs", "yEs" will be recognized as a positive answer).

见题面 Input 部分

见题面 Output 部分

In the first test case, for example, $n = 100$ works. $S(100) = 1$, $S(101) = 2$.

In the second test case, it can be shown that $S(n) \neq S(n+1)$ for all $n$; therefore, the answer is No.

In the fourth test case, $n = 10^{111}-1$ works, which is a number consisting of $111$ digits of $9$.