P7657 [CF1982B] Collatz Conjecture
普及-
题目描述

Recently, the first-year student Maxim learned about the Collatz conjecture, but he didn't pay much attention during the lecture, so he believes that the following process is mentioned in the conjecture:

There is a variable $x$ and a constant $y$. The following operation is performed $k$ times:

  • increase $x$ by $1$, then
  • while the number $x$ is divisible by $y$, divide it by $y$.

For example, if the number $x = 16$, $y = 3$, and $k = 2$, then after one operation $x$ becomes $17$, and after another operation $x$ becomes $2$, because after adding one, $x = 18$ is divisible by $3$ twice.

Given the initial values of $x$, $y$, and $k$, Maxim wants to know what is the final value of $x$.

Input

Each test consists of multiple test cases. The first line contains an integer $t$ ($1 \le t \le 10^{4}$) — the number of test cases. Then follows the description of the test cases.

The only line of each test case contains three integers $x$, $y$, and $k$ ($1 \le x, k \le 10^{9}$, $2 \le y \le 10^{9}$) — the initial variable, constant and the number of operations.

Output

For each test case, output a single integer — the number obtained after applying $k$ operations.

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
13 1 3 1 2 3 1 24 5 5 16 3 2 2 2 1 1337 18 1 1 2 144133 12345678 3 10 998244353 2 998244353 998244353 123456789 998244352 998244354 998241111 998244352 998244355 2 9982443 1000000000 1000000000 1000000000
样例输出
2 1 1 2 3 1338 1 16936 1 21180097 6486 1 2
提示

In the first test case, there is only one operation applied to $x = 1$, resulting in $x$ becoming $2$.

In the second test case, for $x = 2$, within one operation, one is added to $x$ and it's divided by $y = 3$, resulting in $x$ becoming $1$.

In the third test case, $x$ changes as follows:

  • After the first operation, $x = 1$, because $24 + 1 = 25$ and $25$ is divisible by $y = 5$ twice within one operation.
  • After the second operation, $x = 2$.
  • After the third operation, $x = 3$.
  • After the fourth operation, $x = 4$.
  • After the fifth operation, $x = 1$.