P6456 [CF1903F] Babysitting
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题目描述

Theofanis wants to play video games, however he should also take care of his sister. Since Theofanis is a CS major, he found a way to do both. He will install some cameras in his house in order to make sure his sister is okay.

His house is an undirected graph with $n$ nodes and $m$ edges. His sister likes to play at the edges of the graph, so he has to install a camera to at least one endpoint of every edge of the graph. Theofanis wants to find a vertex cover that maximizes the minimum difference between indices of the chosen nodes.

More formally, let $a_1, a_2, \ldots, a_k$ be a vertex cover of the graph. Let the minimum difference between indices of the chosen nodes be the minimum $\lvert a_i - a_j \rvert$ (where $i \neq j$) out of the nodes that you chose. If $k = 1$ then we assume that the minimum difference between indices of the chosen nodes is $n$.

Can you find the maximum possible minimum difference between indices of the chosen nodes over all vertex covers?

Input

The first line contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases.

The first line of each test case contains two integers $n$ and $m$ ($1 \le n \le 10^{5}, 1 \le m \le 2 \cdot 10^{5}$) — the number of nodes and the number of edges.

The $i$-th of the following $m$ lines in the test case contains two positive integers $u_i$ and $v_i$ ($1 \le u_i,v_i \le n$), meaning that there exists an edge between them in the graph.

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^{5}$.

It is guaranteed that the sum of $m$ over all test cases does not exceed $2 \cdot 10^{5}$.

Output

For each test case, print the maximum minimum difference between indices of the chosen nodes over all vertex covers.

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
3 7 6 1 2 1 3 1 4 1 6 2 3 5 7 3 3 1 2 1 3 1 1 2 4 1 2 1 2 2 1 1 1
样例输出
2 3 2
提示

In the first test case, we can install cameras at nodes $1$, $3$, and $7$, so the answer is $2$.

In the second test case, we can install only one camera at node $1$, so the answer is $3$.