P6312 [CF1984H] Tower Capturing
NOI
题目描述

There are $n$ towers at $n$ distinct points $(x_1, y_1), (x_2, y_2), \ldots, (x_n, y_n)$, such that no three are collinear and no four are concyclic. Initially, you own towers $(x_1, y_1)$ and $(x_2, y_2)$, and you want to capture all of them. To do this, you can do the following operation any number of times:

  • Pick two towers $P$ and $Q$ you own and one tower $R$ you don't own, such that the circle through $P$, $Q$, and $R$ contains all $n$ towers inside of it.
  • Afterwards, capture all towers in or on triangle $\triangle$, including $R$ itself.

Count the number of attack plans of minimal length. Note that it might not be possible to capture all towers, in which case the answer is $0$.

Since the answer may be large, output it modulo $998\,244\,353$.

Input

The first line contains a single integer $t$ ($1 \leq t \leq 250$) — the number of test cases.

The first line of each test case contains a single integer $n$ ($4 \leq n \leq 100$) — the number of towers.

The $i$-th of the next $n$ lines contains two integers $x_i$ and $y_i$ ($-10^4 \leq x_i, y_i \leq 10^4$) — the location of the $i$-th tower. Initially, you own towers $(x_1, y_1)$ and $(x_2, y_2)$.

All towers are at distinct locations, no three towers are collinear, and no four towers are concyclic.

The sum of $n$ over all test cases does not exceed $1000$.

Output

For each test case, output a single integer — the number of attack plans of minimal length after which you capture all towers, modulo $998\,244\,353$.

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
3 5 1 1 2 5 3 3 4 2 5 4 6 1 1 3 3 1 2 2 1 3 10000 19 84 7 2 7 -4 -3 -3 6 3 1 -5 2 1 -4 -1 7
样例输出
1 0 10
提示

In the first test case, there is only one possible attack plan of shortest length, shown below.

  • Use the operation with $P =$ tower $1$, $Q =$ tower $2$, and $R =$ tower $5$. The circle through these three towers contains all towers inside of it, and as a result towers $3$ and $5$ are captured.
  • Use the operation with $P =$ tower $5$, $Q =$ tower $1$, and $R =$ tower $4$. The circle through these three towers contains all towers inside of it, and as a result tower $4$ is captured.

In the second case, for example, you can never capture the tower at $(3, 10\,000)$.