题目描述
For $k$ positive integers $x_1, x_2, \ldots, x_k$, the value $\gcd(x_1, x_2, \ldots, x_k)$ is the greatest common divisor of the integers $x_1, x_2, \ldots, x_k$ — the largest integer $z$ such that all the integers $x_1, x_2, \ldots, x_k$ are divisible by $z$.
You are given three arrays $a_1, a_2, \ldots, a_n$, $b_1, b_2, \ldots, b_n$ and $c_1, c_2, \ldots, c_n$ of length $n$, containing positive integers.
You also have a machine that allows you to swap $a_i$ and $b_i$ for any $i$ ($1 \le i \le n$). Each swap costs you $c_i$ coins.
Find the maximum possible value of $$\gcd(a_1, a_2, \ldots, a_n) + \gcd(b_1, b_2, \ldots, b_n)$$ that you can get by paying in total at most $d$ coins for swapping some elements. The amount of coins you have changes a lot, so find the answer to this question for each of the $q$ possible values $d_1, d_2, \ldots, d_q$.
Input
There are two integers on the first line — the numbers $n$ and $q$ ($1 \leq n \leq 5 \cdot 10^5$, $1 \leq q \leq 5 \cdot 10^5$).
On the second line, there are $n$ integers — the numbers $a_1, a_2, \ldots, a_n$ ($1 \leq a_i \leq 10^8$).
On the third line, there are $n$ integers — the numbers $b_1, b_2, \ldots, b_n$ ($1 \leq b_i \leq 10^8$).
On the fourth line, there are $n$ integers — the numbers $c_1, c_2, \ldots, c_n$ ($1 \leq c_i \leq 10^9$).
On the fifth line, there are $q$ integers — the numbers $d_1, d_2, \ldots, d_q$ ($0 \leq d_i \leq 10^{15}$).
Output
Print $q$ integers — the maximum value you can get for each of the $q$ possible values $d$.
输入格式
见题面 Input 部分
输出格式
见题面 Output 部分
样例输入
样例输出
提示
In the first query of the first example, we are not allowed to do any swaps at all, so the answer is $\gcd(1, 2, 3) + \gcd(4, 5, 6) = 2$. In the second query, one of the ways to achieve the optimal value is to swap $a_2$ and $b_2$, then the answer is $\gcd(1, 5, 3) + \gcd(4, 2, 6) = 3$.
In the second query of the second example, it's optimal to perform swaps on positions $1$ and $3$, then the answer is $\gcd(3, 3, 6, 9, 3) + \gcd(8, 4, 4, 8, 4) = 7$ and we have to pay $40$ coins in total.