P5206 [CF1409A] Yet Another Two Integers Problem
入门
题目描述

You are given two integers $a$ and $b$.

In one move, you can choose some integer $k$ from $1$ to $10$ and add it to $a$ or subtract it from $a$. In other words, you choose an integer $k \in [1; 10]$ and perform $a := a + k$ or $a := a - k$. You may use different values of $k$ in different moves.

Your task is to find the minimum number of moves required to obtain $b$ from $a$.

You have to answer $t$ independent test cases.

Input

The first line of the input contains one integer $t$ ($1 \le t \le 2 \cdot 10^4$) — the number of test cases. Then $t$ test cases follow.

The only line of the test case contains two integers $a$ and $b$ ($1 \le a, b \le 10^9$).

Output

For each test case, print the answer: the minimum number of moves required to obtain $b$ from $a$.

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
6 5 5 13 42 18 4 1337 420 123456789 1000000000 100500 9000
样例输出
0 3 2 92 87654322 9150
提示

In the first test case of the example, you don't need to do anything.

In the second test case of the example, the following sequence of moves can be applied: $13 \rightarrow 23 \rightarrow 32 \rightarrow 42$ (add $10$, add $9$, add $10$).

In the third test case of the example, the following sequence of moves can be applied: $18 \rightarrow 10 \rightarrow 4$ (subtract $8$, subtract $6$).