题目描述
Consider a tree (that is, an undirected connected graph without loops) $T_1$ and a tree $T_2$. Let's define their cartesian product $T_1 \times T_2$ in a following way.
Let $V$ be the set of vertices in $T_1$ and $U$ be the set of vertices in $T_2$.
Then the set of vertices of graph $T_1 \times T_2$ is $V \times U$, that is, a set of ordered pairs of vertices, where the first vertex in pair is from $V$ and the second — from $U$.
Let's draw the following edges:
- Between $(v, u_1)$ and $(v, u_2)$ there is an undirected edge, if $u_1$ and $u_2$ are adjacent in $U$.
- Similarly, between $(v_1, u)$ and $(v_2, u)$ there is an undirected edge, if $v_1$ and $v_2$ are adjacent in $V$.
Please see the notes section for the pictures of products of trees in the sample tests.
Let's examine the graph $T_1 \times T_2$. How much cycles (not necessarily simple) of length $k$ it contains? Since this number can be very large, print it modulo $998244353$.
The sequence of vertices $w_1$, $w_2$, ..., $w_k$, where $w_i \in V \times U$ called cycle, if any neighboring vertices are adjacent and $w_1$ is adjacent to $w_k$. Cycles that differ only by the cyclic shift or direction of traversal are still considered different.
Input
First line of input contains three integers — $n_1$, $n_2$ and $k$ ($2 \le n_1, n_2 \le 4000$, $2 \le k \le 75$) — number of vertices in the first tree, number of vertices in the second tree and the cycle length respectively.
Then follow $n_1 - 1$ lines describing the first tree. Each of this lines contains two integers — $v_i, u_i$ ($1 \le v_i, u_i \le n_1$), which define edges of the first tree.
Then follow $n_2 - 1$ lines, which describe the second tree in the same format.
It is guaranteed, that given graphs are trees.
Output
Print one integer — number of cycles modulo $998244353$.
输入格式
见题面 Input 部分
输出格式
见题面 Output 部分
样例输入
样例输出
提示
The following three pictures illustrate graph, which are products of the trees from sample tests.
In the first example, the list of cycles of length $2$ is as follows:
- «AB», «BA»
- «BC», «CB»
- «AD», «DA»
- «CD», «DC»