P2503 [CF1081H] Palindromic Magic
NOI
题目描述

After learning some fancy algorithms about palindromes, Chouti found palindromes very interesting, so he wants to challenge you with this problem.

Chouti has got two strings $A$ and $B$. Since he likes palindromes, he would like to pick $a$ as some non-empty palindromic substring of $A$ and $b$ as some non-empty palindromic substring of $B$. Concatenating them, he will get string $ab$.

Chouti thinks strings he could get this way are interesting, so he wants to know how many different strings he can get.

Input

The first line contains a single string $A$ ($1 \le |A| \le 2 \cdot 10^5$).

The second line contains a single string $B$ ($1 \le |B| \le 2 \cdot 10^5$).

Strings $A$ and $B$ contain only lowercase English letters.

Output

The first and only line should contain a single integer — the number of possible strings.

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
aa aba
样例输出
6
提示

In the first example, attainable strings are

  • "a" + "a" = "aa",
  • "aa" + "a" = "aaa",
  • "aa" + "aba" = "aaaba",
  • "aa" + "b" = "aab",
  • "a" + "aba" = "aaba",
  • "a" + "b" = "ab".

In the second example, attainable strings are "aa", "aaa", "aaaa", "aaaba", "aab", "aaba", "ab", "abaa", "abaaa", "abaaba", "abab", "ba", "baa", "baba", "bb".

Notice that though "a"+"aa"="aa"+"a"="aaa", "aaa" will only be counted once.