P23995 [AtCoder] String Formation
普及-
题目描述

Problem Statement

Takahashi has a string S consisting of lowercase English letters.
Starting with this string, he will produce a new one in the procedure given as follows.
The procedure consists of $Q operations. In Operation i (1 \leq i \leq Q), an integer T_i$ is provided, which means the following:

  • If T_i = 1: reverse the string S.

  • If T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.

  • If F_i = 1 : Add C_i to the beginning of the string S.

  • If F_i = 2 : Add C_i to the end of the string S.

Help Takahashi by finding the final string that results from the procedure.

Input

Input is given from Standard Input in the following format:
S
Q
Query_1
:
Query_Q

In the 3-rd through the (Q+2)-th lines, Query_i is one of the following:
1

which means T_i = 1, and:
2 F_i C_i

which means T_i = 2.

Output

Print the resulting string.

Constraints

  • $1 \leq |S| \leq 10^5$
  • S consists of lowercase English letters.
  • $1 \leq Q \leq 2 \times 10^5$
  • T_i = 1 or 2.
  • F_i = 1 or 2, if provided.
  • C_i is a lowercase English letter, if provided.

Sample Input 1

a
4
2 1 p
1
2 2 c
1

Sample Output 1

cpa

There will be Q = 4 operations. Initially, S is a.

  • Operation 1: Add p at the beginning of S. S becomes pa.

  • Operation 2: Reverse S. S becomes ap.

  • Operation 3: Add c at the end of S. S becomes apc.

  • Operation 4: Reverse S. S becomes cpa.

Thus, the resulting string is cpa.

Sample Input 2

a
6
2 2 a
2 1 b
1
2 2 c
1
1

Sample Output 2

aabc

There will be Q = 6 operations. Initially, S is a.

  • Operation 1: S becomes aa.

  • Operation 2: S becomes baa.

  • Operation 3: S becomes aab.

  • Operation 4: S becomes aabc.

  • Operation 5: S becomes cbaa.

  • Operation 6: S becomes aabc.

Thus, the resulting string is aabc.

Sample Input 3

y
1
2 1 x

Sample Output 3

xy

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
a 4 2 1 p 1 2 2 c 1
样例输出
cpa