Problem Statement

You are given an integer N. Among the divisors of N! $(= 1 \times 2 \times ... \times N), how many Shichi-Go$ numbers (literally "Seven-Five numbers") are there?
Here, a Shichi-Go number is a positive integer that has exactly 75 divisors.

Input

Input is given from Standard Input in the following format:
N

Output

Print the number of the Shichi-Go numbers that are divisors of N!.

Constraints

• $1 \leq N \leq 100$
• N is an integer.

Sample Input 1

9

Sample Output 1

0

There are no Shichi-Go numbers among the divisors of 9! $= 1 \times 2 \times ... \times 9 = 362880$.

Sample Input 2

10

Sample Output 2

1

There is one Shichi-Go number among the divisors of 10! = 3628800: 32400.

Sample Input 3

100

Sample Output 3

543

见题面 Input 部分

见题面 Output 部分