P23313 [AtCoder] Line Sensor
入门
题目描述

Problem Statement

There is a grid with H rows from top to bottom and W columns from left to right. Let (i, j) denote the square at the i-th row from the top and j-th column from the left.
The squares are described by characters C_{i,j}. If C_{i,j} is ., (i, j) is empty; if it is #, (i, j) contains a box.
For integers $j satisfying 1 \leq j \leq W$, let the integer X_j defined as follows.

  • X_j is the number of boxes in the j-th column. In other words, X_j is the number of integers i such that C_{i,j} is #.

Find all of $X_1, X_2, \dots, X_W$.

Input

The input is given from Standard Input in the following format:
H W
$C_{1,1}C_{1,2}\dots C_{1,W}$
$C_{2,1}C_{2,2}\dots C_{2,W}$
$\vdots$
$C_{H,1}C_{H,2}\dots C_{H,W}$

Output

Print $X_1, X_2, \dots, X_W$ in the following format:
$X_1 X_2 \dots X_W$

Constraints

  • $1 \leq H \leq 1000$
  • $1 \leq W \leq 1000$
  • H and W are integers.
  • C_{i, j} is . or #.

Sample Input 1

3 4

..

.#.#
.#.#

Sample Output 1

1 2 0 3

In the 1-st column, one square, (1, 1), contains a box. Thus, X_1 = 1.
In the 2-nd column, two squares, (2, 2) and (3, 2), contain a box. Thus, X_2 = 2.
In the 3-rd column, no squares contain a box. Thus, X_3 = 0.
In the 4-th column, three squares, (1, 4), (2, 4), and (3, 4), contain a box. Thus, X_4 = 3.
Therefore, the answer is (X_1, X_2, X_3, X_4) = (1, 2, 0, 3).

Sample Input 2

3 7
.......
.......
.......

Sample Output 2

0 0 0 0 0 0 0

There may be no square that contains a box.

Sample Input 3

8 3
.#.

.#.
.#.
.##
..#

.

.##

Sample Output 3

2 7 4

Sample Input 4

5 47
.#..#..#####..#...#..#####..#...#...###...#####
.#.#...#.......#.#...#......##..#..#...#..#....
.##....#####....#....#####..#.#.#..#......#####
.#.#...#........#....#......#..##..#...#..#....
.#..#..#####....#....#####..#...#...###...#####

Sample Output 4

0 5 1 2 2 0 0 5 3 3 3 3 0 0 1 1 3 1 1 0 0 5 3 3 3 3 0 0 5 1 1 1 5 0 0 3 2 2 2 2 0 0 5 3 3 3 3

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
3 4 #..# .#.# .#.#
样例输出
1 2 0 3