P23253 [AtCoder] Making Palindrome
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题目描述

Problem Statement

We have N strings of lowercase English letters: $S_1, S_2, \cdots, S_N$.
Takahashi wants to make a string that is a palindrome by choosing one or more of these strings - the same string can be chosen more than once - and concatenating them in some order of his choice.
The cost of using the string S_i once is C_i, and the cost of using it multiple times is C_i multiplied by that number of times.
Find the minimum total cost needed to choose strings so that Takahashi can make a palindrome.
If there is no choice of strings in which he can make a palindrome, print -1.

Input

Input is given from Standard Input in the following format:
N
S_1 C_1
S_2 C_2
:
S_N C_N

Output

Print the minimum total cost needed to choose strings so that Takahashi can make a palindrome, or -1 if there is no such choice.

Constraints

  • $1 \leq N \leq 50$
  • $1 \leq |S_i| \leq 20$
  • S_i consists of lowercase English letters.
  • $1 \leq C_i \leq 10^9$

Sample Input 1

3
ba 3
abc 4
cbaa 5

Sample Output 1

7

We have ba, abc, and cbaa.
For example, we can use ba once and abc once for a cost of 7, then concatenate them in the order abc, ba to make a palindrome.
Also, we can use abc once and cbaa once for a cost of 9, then concatenate them in the order cbaa, abc to make a palindrome.
We cannot make a palindrome for a cost less than 7, so we should print 7.

Sample Input 2

2
abcab 5
cba 3

Sample Output 2

11

We can choose abcab once and cba twice, then concatenate them in the order abcab, cba, cba to make a palindrome for a cost of 11.

Sample Input 3

4
ab 5
cba 3
a 12
ab 10

Sample Output 3

8

We can choose a once, which is already a palindrome, but it is cheaper to concatenate ab and cba.

Sample Input 4

2
abc 1
ab 2

Sample Output 4

-1

We cannot make a palindrome, so we should print -1.

输入格式

见题面 Input 部分

输出格式

见题面 Output 部分

样例输入
3 ba 3 abc 4 cbaa 5
样例输出
7