Chef has two numbers X and Y. Chef wants to find three integers A, B, and C such that:
-1000 ≤ A, B, C ≤ 1000
mean([A, B, C]) = X
median([A, B, C]) = Y

Can you help Chef find such three integers?

As $a reminder, mean([P, Q, R]) = \frac{P + Q + R}{3}$ and median([P, Q, R]) is the element at the 2^{nd} (middle) position after we sort [P, Q, R] in non-decreasing order.

------ Input Format ------

• The first line contains a single integer T — the number of test cases. Then the test cases follow.
• The first and only line of each test case contains two space-separated integers X and Y — the required mean and median of the three integers.

------ Output Format ------

For each test case, output three integers A, B, C which satisfy the given conditions.

It is guaranteed that an answer always exists under the given constraints.

If multiple answers exist, output any.

------ Constraints ------

$1 ≤ T ≤ 10^{5}$
$-100 ≤X, Y ≤100$

----- Sample Input 1 ------
3
5 5
67 100
4 5

----- Sample Output 1 ------
5 5 5
0 100 101
0 5 7
----- explanation 1 ------
Test Case 1: $mean([5, 5, 5]) = \frac{5 + 5 + 5}{3} = 5$, $median([5, 5, 5]) = 5$.

Test Case 2: $mean([0, 100, 101]) = \frac{0 + 100 + 101}{3} = \frac{201}{3} = 67$, $median([0, 100, 101]) = 100$.

Test Case 3: $mean([0, 5, 7]) = \frac{0 + 5 + 7}{3} = 4$, $median([0, 5, 7]) = 5$.

见题面

见题面