For 3 distinct prime integers A, B, and C (1 < A,B,C < 2^{30}), we define positive integers X, Y, and Z as:
$X = A\oplus B, Y = B\oplus C$, and $Z = C\oplus A$, where $\oplus$ denotes the [bitwise XOR] operation.

Given only two integers X and Y and the fact that at least one integer amongst X, Y, and Z is odd, find the values of A, B, and C.

Note:
You need to print the integers A, B, and C in ascending order.
It is guaranteed in the input that a unique answer exists.

------ Input Format ------

• The first line contains one integer T — the number of test cases. Then T test cases follow.
• Each test case consists of one line which contains 2 integers X and Y.

------ Output Format ------

• For each test case, print 3 integers — A , B, and C in ascending order where (1 < A,B,C < 2^{30}).

------ Constraints ------

$1 ≤ T ≤ 10^{5}$
$1 ≤ X, Y< 2^{30}$

----- Sample Input 1 ------
2
1 6
9 15
----- Sample Output 1 ------
2 3 5
2 11 13
----- explanation 1 ------
Test Case $1$: The answer is $A=2, B=3, C=5$. Thus, $X=2\oplus 3 = 1, Y = 3\oplus 5 = 6, Z = 2\oplus 5 = 7$. Note that $X$ and $Y$ are same as mentioned in input and the values $X$ as well as $Z$ are odd.

Test Case $2$: The answer is $A=11, B=2, C=13$. Thus, $X=11\oplus 2 = 9, Y = 2\oplus 13 = 15, Z = 11\oplus 13 = 6$. Note that $X$ and $Y$ are same as mentioned in input and the values $X$ as well as $Y$ are odd.
Thus, the values of $A, B,$ and $C$ in ascending order are $2, 11,$ and $13$.

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