题目描述
Read problems statements in [Mandarin Chinese], [Russian], and [Bengali] as well.
You are given an array A with N integers. You have to tell Chef whether this array is closed under multiplication.
We say that an array is closed under multiplication if, for all sequences 1 ≤ $S_{1} < S_{2} < \dots < S_{k}$ ≤ N, there exists 1 ≤ x ≤ N such that $A_{S_{1}} \cdot A_{S_{2}} \cdot \dots \cdot A_{S_{k}} = A_{x}$.
Output 1 if it is closed, and 0 otherwise.
------ Input Format ------
- The first line of the input contains T - the number of test cases. Then the test cases follow.
- The first line of each test case contains a single integer - N
- The second line of each test case contains N space-separated integers - the i^{th} of which is A_{i}
------ Output Format ------
For each test case, output the answer on a new line. Output 1 if A is closed under multiplication, and 0 otherwise.
------ Constraints ------
$1 ≤ T, N ≤ 10^{5}$
$-10^{9} ≤ A_{i} ≤ 10^{9}$
- The sum of $N$ across all test cases does not exceed $10^{6}$
----- Sample Input 1 ------
3
3
1 0 3
3
1 -1 -1
3
1 3 3
----- Sample Output 1 ------
1
1
0
----- explanation 1 ------
Test case $1$: $[1, 0, 3]$ is closed under multiplication.
$A_{1} \cdot A_{2} = 1 \cdot 0 = 0 = A_{2}$
$A_{1} \cdot A_{2} \cdot A_{3} = 1 \cdot 0 \cdot 3 = 0 = A_{2}$
$A_{1} \cdot A_{3} = 1 \cdot 3 = 3 = A_{3}$
$A_{2} \cdot A_{3} = 0 \cdot 3 = 0 = A_{2}$
Therefore, the answer for the first test case is $1$.
Test case $2$: $[1, -1, -1]$ is closed under multiplication.
$A_{1} \cdot A_{2} = 1 \cdot -1 = -1 = A_{2}$
$A_{1} \cdot A_{2} \cdot A_{3} = 1 \cdot -1 \cdot -1 = 1 = A_{1}$
$A_{1} \cdot A_{3} = 1 \cdot -1 = -1 = A_{2}$
$A_{2} \cdot A_{3} = -1 \cdot -1 = 1 = A_{1}$
Therefore, the answer for the second test case is $1$.
Test case $3$: $A_{2} \cdot A_{3} = 3 \cdot 3 = 9$ is not present in the array. Therefore, $[1, 3, 3]$ is not closed under multiplication, and the answer is $0$.
输入格式
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输出格式
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