题目描述
Little Bobby loves chocolate. He frequently goes to his favorite $5\text{&}10$ store, Penny Auntie, to buy them. They are having a promotion at Penny Auntie. If Bobby saves enough wrappers, he can turn them in for a free chocolate.
Example
$n=15$
$c=3$
$m=2$
He has $15$ to spend, bars cost $3$, and he can turn in $2$ wrappers to receive another bar. Initially, he buys $5$ bars and has $5$ wrappers after eating them. He turns in $4$ of them, leaving him with $1$, for $2$ more bars. After eating those two, he has $3$ wrappers, turns in $2$ leaving him with $1$ wrapper and his new bar. Once he eats that one, he has $2$ wrappers and turns them in for another bar. After eating that one, he only has $1$ wrapper, and his feast ends. Overall, he has eaten $5+2+1+1=9$ bars.
Function Description
Complete the chocolateFeast function in the editor below.
chocolateFeast has the following parameter(s):
int n: Bobby's initial amount of money
int c: the cost of a chocolate bar
int m: the number of wrappers he can turn in for a free bar
Returns
int: the number of chocolates Bobby can eat after taking full advantage of the promotion
Note: Little Bobby will always turn in his wrappers if he has enough to get a free chocolate.
Input Format
The first line contains an integer, $\boldsymbol{\boldsymbol{t}}$, the number of test cases to analyze.
Each of the next $\boldsymbol{\boldsymbol{t}}$ lines contains three space-separated integers: $n$, $\textbf{C}$, and $m$. They represent money to spend, cost of a chocolate, and the number of wrappers he can turn in for a free chocolate.
Constraints
$1\leq t\leq1000$
$2\leq n\leq10^5$
$1\leq c\leq n$
$2\leq m\leq n$
Sample Input
STDIN Function
----- --------
3 t = 3 (test cases)
10 2 5 n = 10, c = 2, m = 5 (first test case)
12 4 4 n = 12, c = 4, m = 4 (second test case)
6 2 2 n = 6, c = 2, m = 2 (third test case)
Sample Output
6
3
5
Explanation
Bobby makes the following $3$ trips to the store:
He spends $10$ on $5$ chocolates at $2$ apiece. He then eats them and exchanges all $5$ wrappers to get $1$ more. He eats $\boldsymbol{6}$ chocolates.
He spends his $12$ on $3$ chocolates at $4$ apiece. He has $3$ wrappers, but needs $4$ to trade for his next chocolate. He eats $3$ chocolates.
He spends $\boldsymbol{6}$ on $3$ chocolates at $2$ apiece. He then exchanges $2$ of the $3$ wrappers for $1$ additional piece. Next, he uses his third leftover chocolate wrapper from his initial purchase with the wrapper from his trade-in to do a second trade-in for $1$ more piece. At this point he has $1$ wrapper left, which is not enough to perform another trade-in. He eats $5$ chocolates.
输入格式
见题面
输出格式
见题面