zip([iterable, ...])

This function returns a list of tuples. The $i^{th}$ tuple contains the $i^{th}$ element from each of the argument sequences or iterables.

If the argument sequences are of unequal lengths, then the returned list is truncated to the length of the shortest argument sequence.

Sample Code

print zip([1,2,3,4,5,6],'Hacker')
[(1, 'H'), (2, 'a'), (3, 'c'), (4, 'k'), (5, 'e'), (6, 'r')]

print zip([1,2,3,4,5,6],[0,9,8,7,6,5,4,3,2,1])
[(1, 0), (2, 9), (3, 8), (4, 7), (5, 6), (6, 5)]

A = [1,2,3]
B = [6,5,4]
C = [7,8,9]
X = [A] + [B] + [C]

print zip(*X)
[(1, 6, 7), (2, 5, 8), (3, 4, 9)]

Task

The National University conducts an examination of $N$ students in $\mbox{X}$ subjects.

Your task is to compute the average scores of each student.

$\textit{Average score}=\frac{\textit{Sum of scores obtained in all subjects by a student}}{\textit{Total number of subjects}}$

The format for the general mark sheet is:

Student ID → 12_____3_____4_____5
Subject 1 | 89 90 78 93 80
Subject 2 | 90 91 85 88 86
Subject 3 | 91 92 83 89 90.5
|______
Average 90 91 82 90 85.5

Input Format

The first line contains $N$ and $\mbox{X}$ separated by a space.

The next $\mbox{X}$ lines contains the space separated marks obtained by students in a particular subject.

Constraints

$0<N\leq100$

$0<X\leq100$

Output Format

Print the averages of all students on separate lines.

The averages must be correct up to $\mbox{1}$ decimal place.

Sample Input
5 3
89 90 78 93 80
90 91 85 88 86
91 92 83 89 90.5

Sample Output
90.0
91.0
82.0
90.0
85.5

Explanation

Marks obtained by student 1: $89,90,91$

Average marks of student 1:

$270/3=90$

Marks obtained by student 2: $90,91,92$

Average marks of student 2:

$273/3=91$

Marks obtained by student 3: $78,85,83$

Average marks of student 3:

$246/3=82$

Marks obtained by student 4: $93,88,89$

Average marks of student 4:

$270/3=90$

Marks obtained by student 5: $80,86,90.5$

Average marks of student 5:

$256.5/3=85.5$

见题面

见题面