题目描述
Given two integers ‘a’ and ‘m’. The task is to find the smallest modular multiplicative inverse of ‘a’ under modulo ‘m’.
Example 1:
Input:
a = 3
m = 11
Output: 4
Explanation: Since (43) mod 11 = 1, 4
is modulo inverse of 3. One might think,
15 also as a valid output as "(153)
mod 11" is also 1, but 15 is not in
ring {0, 1, 2, ... 10}, so not valid.
Example 2:
Input:
a = 10
m = 17
Output: 12
Explanation: Since (12*10) mod 17 = 1,
12 is the modulo inverse of 10.
Your Task:
You don't need to read input or print anything. Your task is to complete the function function modInverse() that takes a and m as input parameters and returns modular multiplicative inverse of ‘a’ under modulo ‘m’. If the modular multiplicative inverse doesn't exist return -1.
Expected Time Complexity : O(m)
Expected Auxilliary Space : O(1)
Constraints:
1 <= a <= 10^{4}
1 <= m <= 10^{4}
输入格式
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输出格式
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