Instead of writing,$a \times (b+c) = a \times b + a \times c$, Joe by mistakenly swapped the $\times$ and + signs on the left hand side. The equation became, $a+(b \times c)= a \times b + a \times c$ ?

Joe somehow knew the value of a, but forgot the values of b and c such that the equation is satisfied. Can you help him find how many ordered pairs $(b,c)$ satisfy the above equation?
If there exists infinite ordered pair, output -1.
Note: $a,b,c$ are integers

------ Input ------

Single line containing a single integer $a$

------ Output ------

Single line containing one integer, denoting the number of ordered set (b,c)

------ Constraints ------

$$|a| ≤ 10^{18}$$

------ Sample Input ------

2

------ Sample Output ------

4

------ Explanation ------

Possible ordered pairs are $(0,1), (1,0), (3,4), (4,3)$

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