Given a 32 bit unsigned integer num and an integer i. Perform following operations on the number -
1. Get ith bit
2. Set ith bit
3. Clear ith bit
Note : For better understanding, we are starting bits from 1 instead 0. (1-based)
Example 1:
Input: 70 3
Output: 1 70 66
Explanation: Bit at the 3rd position from LSB is 1. (1 0 0 0 1 1 0)
The value of the given number after setting the 3rd bit is 70.
The value of the given number after clearing 3rd bit is 66. (1 0 0 0 0 1 0)
Example 2:
Input: 8 1
Output: 0 9 8
Explanation: Bit at the first position from LSB is 0. (1 0 0 0)
The value of the given number after setting the 1st bit is 9. (1 0 0 1)
The value of the given number after clearing 1st bit is 8. (1 0 0 0)

Your Task:
Complete the function bitManipulation() which takes two integers num and i as input and prints the results after each operation separted by a space in the same line. You don't have to print any new lines after printing the output, that will be handled by driver code.

Constraints:
0<=num<=10^{9}
1<=i<=32

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