题目描述
Given an integer N, find it's parity.
Parity of a number refers to the number of 1 bits it contains. The number has “odd parity”, if it contains odd number of 1-bits and is “even parity” if it contains even number of 1-bits.
Example 1:
Input:
N = 13
Output: odd
Explanation:
(13){10} = (1101) The binary representation
has three 1-bits. So, it's parity is odd.
Example 2:
Input:
N = 9
Output: even
Explanation:
(9){10} = (1001) The binary representation
has two 1-bits. So, it's parity is even.
Your Task:
You don't need to read input or print anything. Your task is to complete the function computeParity() which takes an Integer N as input parameter and returns string "odd" or "even".
Expected Time Complexity: O(log(N))
Expected Auxiliary Space: O(1)
Constraints:
1 <= N <= 10^{5}
输入格式
见题面
输出格式
见题面