Given two strings A and B of equal length, find how many times the corresponding position in the two strings hold exactly the same character. The comparison should not be case sensitive.
Example 1:
Input:
A = choice
B = chancE
Output: 4
Explanation: characters at position 0, 1, 4 and 5
are same in the two strings A and B.
Example 2:
Input:
A = Geek
B = gang
Output: 1
Explanation: charactera at position 0 is the
same in the two strings A and B.
Your Task:
You dont need to read input or print anything. Complete the function sameChar() which takes the two strings A and B as input parameters and returns the count of the characters that are same in A and B.
Expected Time Complexity: O(N) where N is the length of strings A and B.
Expected Auxiliary Space: O(1)
Constraints:
1<= A.length(), B.length() <= 10^{4}

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