Given two force vectors, find out whether they are parallel, perpendicular or neither. Let the first vector be A = a_{1} i +a_{2} j + a_{3} k and the second vector be B = b_{1} i + b_{2} j + b_{3} k.
A.B = a_{1 } b_{1} + a_{2 } b_{2} + a_{3 } b_{3}
A x B = (a2 * b3 - a_{3 } b_{2}) i - (a_{1} * b_{3} - b_{1} a_{3}) j + (a_{1 } b_{2} - a_{2 }* b_{1}) k
|A|^{2} = a12 + a22 + a32
If A.B = 0, then A and B are perpendicular.
If |A X B|^{2} = 0, then A and B are parallel.
Example 1:
Input: A = 3i + 2j + k, B = 6i + 4j + 2k
Output: 1
Explanation: |A X B|^{2 }= 0
Example 2:
Input: A = 4i + 6j + k, B = i - 1j + 2k
Output: 2
Explanation: A.B = 0

Your Task:
You don't need to read or print anything. Your task is to complete the function find() which takes A and B vector as parameter and returns 1 if they are parallel to each other, 2 if they are perpendicular to each other or 0 otherwise. A and B vectors will contain (a1,a2,a3) and (b1,b2,b3) respectively.

Expected Time Complexity: O(1)
Expected Space Complexity: O(1)

Constraints:
-100 <= Component <= 100

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